Given to whole numbers $a, b$, you are expected to caculate the result of expression $a+b$.

Two integer a,b $(-10^5 \le a,b \le 10^5)$

Output the result of $a+b$.

Here are some example solution with various programming languages.

1. C programming language

   #include <stdio.h>
   int main()
   {
   int a,b;
   while(scanf("%d %d",&a, &b) != EOF)
       printf("%d\n",a+b);
   return 0;
   }

2. C++ programming language

   #include <iostream>
   using namespace std;
   int main()
   {
   int a,b;
   while(cin >> a >> b)
       cout << a+b << endl;
   }

3. Pascal/Delphi programming language

   program p1001(Input,Output);
   var
   a,b:Integer;
   begin
   while not eof(Input) do
    begin
      Readln(a,b);
      Writeln(a+b);
    end;
   end

4. Java programming language

   import java.util.Scanner;
   public class Main {
   public static void main(String[] args) {
       Scanner in = new Scanner(System.in);
       while (in.hasNextInt()) {
           int a = in.nextInt();
           int b = in.nextInt();
           System.out.println(a + b);
       }
   }
   }

5. shell scripts

   a=gets.chomp
   b="0"
   a.each_line(" "){
   |d|
   b=b+"+"+d
   }
   puts eval(b)
   read a b
   echo ((a+$b))

6. Python programming language

   import sys
   for line in sys.stdin:
   a = line.split()
   print int(a[0]) + int(a[1])

7. PHP scripts

   <?php
   while (fscanf(STDIN, "%d%d", a,b) == 2) {
   print (a+b) . "\n";
   }
   ?>

8. perl scripts

   #! /usr/bin/perl -w
   while(<>){
   chomp;
   (a,b)=split(/\s/,$_);
   printf "%d\n",a+b;
   }

9. C# programming language

   using System;
   public class Sum
   {
   public static void Main()
   {
       //string token = Console.ReadLine();
       //int test = int.Parse(token);
       for(int k = 0; k < 1;k++){
            string[] tokens = Console.ReadLine().Split(' ');
            Console.WriteLine(int.Parse(tokens[0]) + int.Parse(tokens[1]));
       }
   }
   }