2531.Multipliers

Time Limit: 1s Memory Limit: 256MB

Ayrat has number n, represented as it's prime factorization pi of size m, i.e. n=p1 \cdot p2 \cdot ... \cdot pm. Ayrat got secret information that that the product of all divisors of n taken modulo 109+7 is the password to the secret data base. Now he wants to calculate this value.

Input Format(From the terminal/stdin)

The first line of the input contains a single integer m (1 \le m \le 200000)- the number of primes in factorization of n.

The second line contains m primes numbers pi (2 \le pi \le 200000).

Output Format(To the terminal/stdout)

Print one integer- the product of all divisors of n modulo 109+7.

Sample Input 1

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2
2 3
 \n
 · \n

Sample Output 1

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36
  \n

Sample Input 2

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3
2 3 2
 \n
 · · \n

Sample Output 2

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1728
    \n

Hints

In the first sample n=2 \cdot 3=6. The divisors of 6 are 1, 2, 3 and 6, their product is equal to 1 \cdot 2 \cdot 3 \cdot 6=36.

In the second sample 2 \cdot 3 \cdot 2=12. The divisors of 12 are 1, 2, 3, 4, 6 and 12. 1 \cdot 2 \cdot 3 \cdot 4 \cdot 6 \cdot 12=1728.

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