2586.Lipshitz Sequence

Time Limit: 1s Memory Limit: 256MB

A function 2586_1.png is called Lipschitz continuous if there is a real constant K such that the inequality |f(x)-f(y)| \le K \cdot |x-y| holds for all 2586_2.png. We'll deal with a more... discrete version of this term.For an array 2586_3.png, we define it's Lipschitz constant 2586_4.png as follows: if n \lt 2, 2586_5.png if n \ge 2, 2586_6.png over all 1 \le i \lt j \le n In other words, 2586_7.png is the smallest non-negative integer such that |h[i]-h[j]| \le L \cdot |i-j| holds for all 1 \le i,j \le n.You are given an array 2586_8.png of size n and q queries of the form [l,r]. For each query, consider the subarray 2586_9.png; determine the sum of Lipschitz constants of all subarrays of 2586_10.png.

Input Format(From the terminal/stdin)

Input The first line of the input contains two space-separated integers n and q (2 \le n \le 100000 and 1 \le q \le 100)- the number of elements in array 2586_8.png and the number of queries respectively.The second line contains n space-separated integers 2586_11.png (2586_12.png).The following q lines describe queries. The i-th of those lines contains two space-separated integers li and ri (1 \le li \lt ri \le n).

Output Format(To the terminal/stdout)

Output Print the answers to all queries in the order in which they are given in the input. For the i-th query, print one line containing a single integer- the sum of Lipschitz constants of all subarrays of 2586_13.png.

Sample Input 1

Copy
10 4
1 5 2 9 1 3 4 2 1 7
2 4
3 8
7 10
1 9
  · \n
 · · · · · · · · · \n
 · \n
 · \n
 ·  \n
 · \n

Sample Output 1

Copy
17
82
23
210
  \n
  \n
  \n
   \n

Sample Input 2

Copy
7 6
5 7 7 4 6 6 2
1 2
2 3
2 6
1 7
4 7
3 5
 · \n
 · · · · · · \n
 · \n
 · \n
 · \n
 · \n
 · \n
 · \n

Sample Output 2

Copy
2
0
22
59
16
8
 \n
 \n
  \n
  \n
  \n
 \n

Hints

In the first query of the first sample, the Lipschitz constants of subarrays of 2586_14.png with length at least 2 are: 2586_15.png2586_16.png2586_17.png The answer to the query is their sum.

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